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ICMC 2018/19 Round 1, Problem 2

Source: Imperial College Mathematics Competition 2018/19 - Round 1

August 7, 2020
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Problem Statement

This question, again, comprises two independent parts.
(i) Show that if (k+1)(k+1) integers are chosen from {1,2,3,...,2k+1}\left\{1,2,3,...,2k+1\right\}, then among the chosen integers there are always two that are coprime.
(ii) Let A={1,2,,n}.A=\left\{1,2,\ldots,n\right\}. Prove that if n>11n>11 then there is a bijective map f:AAf: A\to A with the property that, for every aAa\in A, exactly one of f(f(f(f(a))))=af(f(f(f(a))))=a and f(f(f(f(f(a)))))=af(f(f(f(f(a)))))=a holds.