MathDB
rhombus BCDE ouside equilateral ABE, AF <BD wanted

Source: Oral Moscow Geometry Olympiad 2015 grades 8-9 p5

August 8, 2019
geometric inequalityrhombusEquilateralgeometry

Problem Statement

On the BEBE side of a regular ABEABE triangle, a BCDEBCDE rhombus is built outside it. The segments ACAC and BDBD intersect at point FF. Prove that AF<BDAF <BD.
Back to ProblemsView on AoPS