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locus of AP x CP + BPx DP = 1 where ABCD square of sidelength 1

Source: Switzerland - Swiss MO 2008 p5

July 17, 2020
geometryLocussquare

Problem Statement

Let ABCDABCD be a square with side length 11. Find the locus of all points PP with the property AP⋅CP+BP⋅DP=1AP\cdot CP + BP\cdot DP = 1.
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