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Indian RMO - Paper -4[1]

Source:

December 12, 2013
geometry

Problem Statement

Let ω\omega be a circle with centre OO. Let γ\gamma be another circle passing through OO and intersecting ω\omega at points AA and BB. AA diameter CDCD of ω\omega intersects γ\gamma at a point PP different from OO. Prove that APC=BPD\angle APC= \angle BPD