Infinitely many terms divisible by 1986
Source: Canadian Mathematical Olympiad - 1986 - Problem 5.
July 3, 2011
pigeonhole principlemodular arithmeticinductionalgebra unsolvedalgebra
Problem Statement
Let , , , be a sequence of integers satisfying the recurrence relation . Suppose and . Prove that 1986 divides infinitely many terms of the sequence.