MathDB
Inequality

Source: 2016 Taiwan TST Round 3

July 23, 2016
inequalities

Problem Statement

Let x,y,zx,y,z be positive real numbers satisfying x+y+z=1x+y+z=1. Find the smallest kk such that x2y21z+y2z21x+z2x21yk3xyz\frac{x^2y^2}{1-z}+\frac{y^2z^2}{1-x}+\frac{z^2x^2}{1-y}\leq k-3xyz.