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\frac{a+b}{2} \frac{a^2+b^2}{2} \frac{a^3+b^3}{2} \leq \frac{a^6+b^6}{2}.

Source: Polish MO Finals 1959 p1

August 29, 2024
inequalitiesalgebra

Problem Statement

Prove that for any numbers a a and b b the inequality holds a+b2a2+b22a3+b32a6+b62. \frac{a+b}{2} \cdot \frac{a^2+b^2}{2} \cdot \frac{a^3+b^3}{2} \leq \frac{a^6+b^6}{2}.