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TOT 1998 Spring AJ2 MD = MG inside parallelogram, <MAD = <AMO

Source:

May 11, 2020
geometryparallelogramequal segmentsequal angles

Problem Statement

ABCDABCD is a parallelogram. A point MM is found on the side ABAB or its extension such that ∠MAD=∠AMO\angle MAD = \angle AMO where OO is the intersection point of the diagonals of the parallelogram. Prove that MD=MGMD = MG.
(M Smurov)
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