MathDB
Putnam 1952 A5

Source:

May 29, 2022
Putnam

Problem Statement

Let aj(j=1,2,,n)a_j (j = 1, 2, \ldots, n) be entirely arbitrary numbers except that no one is equal to unity. Prove a1+i=2naij=1i1(1aj)=1j=1n(1aj). a_1 + \sum^n_{i=2} a_i \prod^{i-1}_{j=1} (1 - a_j) = 1 - \prod^n_{j=1} (1 - a_j).