MathDB
Complex polynomial

Source: 2024 CTST P23

March 29, 2024
polynomialalgebracomplex analysis2024 CTSTChina TST

Problem Statement

P(z)=anzn++a1z+z0P(z)=a_nz^n+\dots+a_1z+z_0, with an0a_n\neq 0 is a polynomial with complex coefficients, such that when z=1|z|=1, P(z)1|P(z)|\leq 1. Prove that for any 0kn10\leq k\leq n-1, ak1an2|a_k|\leq 1-|a_n|^2.
Proposed by Jingjun Han