MathDB
Angle bisector

Source: Canada 1969, Problem 5

May 14, 2006
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Problem Statement

Let ABCABC be a triangle with sides of length aa, bb and cc. Let the bisector of the angle CC cut ABAB in DD. Prove that the length of CDCD is 2abcosC2a+b. \frac{2ab\cos \frac{C}{2}}{a+b}.