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AB+CD≥BC+AD in convex ABCD

Source: Czech-Polish-Slovak Match 2007-P6

September 14, 2011
geometry unsolvedgeometry

Problem Statement

Let ABCDABCD be a convex quadrilateral. A circle passing through the points AA and DD and a circle passing through the points BB and CC are externally tangent at a point PP inside the quadrilateral. Suppose that PAB+PDC90\angle PAB+\angle PDC \leq 90^{\circ} and PBA+PCD90.\angle PBA+\angle PCD \leq 90^{\circ}. Prove that AB+CDBC+AD.AB+CD\geq BC+AD.