A cylindrical hole of radius r is bored through a cylinder of radiues R (r≤R) so that the axes intersect at right angles.
i) Show that the area of the larger cylinder which is inside the smaller one can be expressed in the form
S=8r2∫01(1−v2)(1−m2v2)1−v2dv,wherem=Rr.
ii) If K=∫01(1−v2)(1−m2v2)1dv and E=∫011−v21−m2v2dv.
show that
S=8[R2E−(R2−r2)K].