MathDB
ASU 492 All Soviet Union MO 1989 simila triangles wanted

Source:

August 13, 2019
geometrysimilar trianglesequal ratiosequal angles

Problem Statement

ABCABC is a triangle. A′,B′,C′A' , B' , C' are points on the segments BC,CA,ABBC, CA, AB respectively. ∠B′A′C′=∠A\angle B' A' C' = \angle A , AC′C′B=BA′A′C=CB′B′A\frac{AC'}{C'B} = \frac{BA' }{A' C} = \frac{CB'}{B'A}. Show that ABCABC and A′B′C′A'B'C' are similar.
Back to ProblemsView on AoPS