MathDB
(100!)^99 > (99!)^100 > (100!)^98 .

Source: Assara 2024 S5

October 14, 2024
algebrainequalities

Problem Statement

Prove that (100!)99>(99!)100>(100!)98(100!)^{99} > (99!)^{100} > (100!)^{98}. K.A.Sukhov