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Divisors of...divisors

Source: 2016 All-Russian Olympiad,Problem 9.3

June 7, 2016
number theoryDivisorsgreatest common divisor

Problem Statement

Alexander has chosen a natural number N>1N>1 and has written down in a line,and in increasing order,all his positive divisors d1<d2<<dsd_1<d_2<\ldots <d_s (where d1=1d_1=1 and ds=Nd_s=N).For each pair of neighbouring numbers,he has found their greater common divisor.The sum of all these s1s-1 numbers (the greatest common divisors) is equal to N2N-2.Find all possible values of NN.