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8
I 8
I 8
Source:
May 25, 2007
floor function
calculus
derivative
inequalities
Problem Statement
Prove that
⌊
n
3
+
n
+
1
3
+
n
+
2
3
⌋
=
⌊
27
n
+
26
3
⌋
\lfloor \sqrt[3]{n}+\sqrt[3]{n+1}+\sqrt[3]{n+2}\rfloor =\lfloor \sqrt[3]{27n+26}\rfloor
⌊
3
n
+
3
n
+
1
+
3
n
+
2
⌋
=
⌊
3
27
n
+
26
⌋
for all positive integers
n
n
n
.
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