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Incenters equidistant from midpoint of arc ABC

Source: All-Russian Olympiad 2006 finals, problem 10.6

May 7, 2006
geometryincentercircumcircletrapezoidcomplex numbersgeometry proposed

Problem Statement

Let KK and LL be two points on the arcs ABAB and BCBC of the circumcircle of a triangle ABCABC, respectively, such that KLACKL\parallel AC. Show that the incenters of triangles ABKABK and CBLCBL are equidistant from the midpoint of the arc ABCABC of the circumcircle of triangle ABCABC.