MathDB
Concurency

Source: Turkey TST 2014 Day 2 Problem 5

March 12, 2014
geometrycircumcirclegeometric transformationhomothetytrigonometryconicsinequalities

Problem Statement

A circle ω\omega cuts the sides BC,CA,ABBC,CA,AB of the triangle ABCABC at A1A_1 and A2A_2; B1B_1 and B2B_2; C1C_1 and C2C_2, respectively. Let PP be the center of ω\omega. AA' is the circumcenter of the triangle A1A2PA_1A_2P, BB' is the circumcenter of the triangle B1B2PB_1B_2P, CC' is the circumcenter of the triangle C1C2PC_1C_2P. Prove that AA,BBAA', BB' and CCCC' concur.