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Some Equalities about Function

Source: 1984 National High School Mathematics League, Exam One, Problem 6

February 22, 2020
function

Problem Statement

If F(1x1+x)=xF(\frac{1-x}{1+x})=x, then (A)F(2x)=2F(x)(B)F(x)=F(1+x1x)\text{(A)}F(-2-x)=-2-F(x)\qquad\text{(B)}F(-x)=F(\frac{1+x}{1-x}) (C)F(1x)=F(x)(D)F(F(x))=x\text{(C)}F(\frac{1}{x})=F(x)\qquad\text{(D)}F(F(-x))=-x