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2
2015 Algebra Tiebreaker #2
2015 Algebra Tiebreaker #2
Source:
July 1, 2022
2015
Algebra Tiebreaker
Problem Statement
Compute
∑
n
=
0
∞
n
+
1
2
n
.
\sum_{n=0}^\infty\frac{n+1}{2^n}.
n
=
0
∑
∞
2
n
n
+
1
.
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