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Albania BMO TST Problem 4

Source:

April 1, 2017
geometry

Problem Statement

The incircle of A0B0C0 \triangle A_{0}B_{0}C_{0}, meets legs B0C0B_{0}C_{0}, C0A0C_{0}A_{0}, A0B0A_{0}B_{0}, respectively on points AA, BB, CC, and the incircle of ABC \triangle ABC, with center II, meets legs BCBC, CACA, ABAB, on points A1A_{1}, B1B_{1}, C1C_{1}, respectively. We write with σ(ABC) \sigma (ABC), and σ(A1B1C1) \sigma (A_{1}B_{1}C_{1}) the areas of ABC \triangle ABC, and A1B1C1 \triangle A_{1}B_{1}C_{1} respectively. Prove that if σ(ABC)=2σ(A1B1C1) \sigma (ABC)=2 \sigma (A_{1}B_{1}C_{1}), then lines AA0AA_{0}, BB0BB_{0}, CC0CC_{0} are concurrent.