MathDB
Equal distance from the Incenter

Source: 239 2009 J5

July 29, 2020
geometryincenter

Problem Statement

On the sides AB,BCAB, BC and CACA of triangle ABCABC, points K,LK, L and MM are selected, respectively, such that AK=AMAK = AM and BK=BLBK = BL. If MLB=CAB\angle{MLB} = \angle{CAB}, Prove that ML=KIML = KI, where II is the incenter of triangle CMLCML.