MathDB
2 + 2\sqrt{28n^2 + 1} is sqaure if it is an integer

Source: 1969 Hungary - Kürschák Competition p1

October 11, 2022
number theoryIntegerPerfect Square

Problem Statement

Show that if 2+228n2+12 + 2\sqrt{28n^2 + 1} is an integer, then it is a square (for nn an integer).