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f(xy) = f(x)f(y) - f(x+y) + 1

Source: IMO 1980 Luxembourg, problem 1

May 6, 2004
functionalgebrafunctional equationIMO Shortlist

Problem Statement

The function ff is defined on the set Q\mathbb{Q} of all rational numbers and has values in Q\mathbb{Q}. It satisfies the conditions f(1)=2f(1) = 2 and f(xy)=f(x)f(y)f(x+y)+1f(xy) = f(x)f(y) - f(x+y) + 1 for all x,yQx,y \in \mathbb{Q}. Determine ff.