Turkish NMO First Round - 2012 Problem - 20 {Combinatorics}
Source:
July 1, 2012
Problem Statement
For each permutation (a1,a2,…,a11) of the numbers 1,2,3,4,5,6,7,8,9,10,11, we can determine at least k of ais when we get (a1+a3,a2+a4,a3+a5,…,a8+a10,a9+a11). k can be at most ?<spanclass=′latex−bold′>(A)</span>11<spanclass=′latex−bold′>(B)</span>6<spanclass=′latex−bold′>(C)</span>5<spanclass=′latex−bold′>(D)</span>2<spanclass=′latex−bold′>(E)</span>None