MathDB
midpoint is foot of altitude (Kharkiv City X 2012 - Ukr)

Source:

March 10, 2020
geometryaltitudeKharkivmidpointConcyclic

Problem Statement

In the acute-angled triangle ABCABC on the sides ACAC and BCBC, points DD and EE are chosen such that points A,B,EA, B, E, and DD lie on one circle. The circumcircle of triangle DECDEC intersects side ABAB at points XX and YY. Prove that the midpoint of segment XYXY is the foot of the altitude of the triangle, drawn from point CC.