MathDB
2005 | a_n x a_{n+31} All-Russian MO 2005 Regional 10.5

Source:

August 26, 2024
number theoryArithmetic Progressiondivisibledivides

Problem Statement

Arithmetic progression a1,a2,...,a_1, a_2, . . . , consisting of natural numbers is such that for any nn the product anan+31a_n \cdot a_{n+31} is divisible by 20052005. Is it possible to say that all terms of the progression are divisible by 20052005?