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Prove that OI is perpendicular to AB (2)

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October 28, 2010
geometrycircumcircletrigonometryGaussEulergeometric transformationhomothety

Problem Statement

Bisectors AA1AA_1 and BB1BB_1 of a right triangle ABC (∠C=90∘)ABC \ (\angle C=90^\circ ) meet at a point I.I. Let OO be the circumcenter of triangle CA1B1.CA_1B_1. Prove that OI⊥AB.OI \perp AB.
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