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angle chasing, OD = BD = 1/3 BC (Kyiv City Olympiad 2010 8.4 9.6)

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July 2, 2020
geometryanglesCircumcenter

Problem Statement

Point OO is the center of the circumcircle of the acute triangle ABCABC. The line AOAO intersects the side BCBC at point DD so that OD=BD=1/3BCOD = BD = 1/3 BC . Find the angles of the triangle ABCABC. Justify the answer.
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