MathDB
ISI 2020 : Problem 6

Source: B.Stat & B.Math Entrance Exam 2020

September 20, 2020
isi2020calculus

Problem Statement

Prove that the family of curves x2a2+λ+y2b2+λ=1\frac{x^2}{a^2+\lambda}+\frac{y^2}{b^2+\lambda}=1 satisfies dydx(a2b2)=(x+ydydx)(xdydxy)\frac{dy}{dx}(a^2-b^2)=\left(x+y\frac{dy}{dx}\right)\left(x\frac{dy}{dx}-y\right)