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n^2(n^2 + 2)^2 , n^4(n^2 + 2)^2, in base n^2 +1, same digits

Source: 1989 Swedish Mathematical Competition p1

March 28, 2021
number theoryDigitsPerfect Square

Problem Statement

Let nn be a positive integer. Prove that the numbers n2(n2+2)2n^2(n^2 + 2)^2 and n4(n2+2)2n^4(n^2 + 2)^2 are written in base n2+1n^2 +1 with the same digits but in opposite order.