MathDB
2016 Latvia National Olympiad 3rd Round Grade12Problem2

Source:

July 22, 2016
geometryincenter

Problem Statement

Triangle ABCABC has incircle ω\omega and incenter II. On its sides ABAB and BCBC we pick points PP and QQ respectively, so that PI=QIPI = QI and PB>QBPB > QB. Line segment QIQI intersects ω\omega in TT. Draw a tangent line to ω\omega passing through TT; it intersects the sides ABAB and BCBC in UU and VV respectively. Prove that PU=UV+VQPU = UV + VQ!