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Today's calculation of Integral 130

Source: Tokyo university of Science entrance exam 2006

July 26, 2006
calculusintegrationlogarithmscalculus computations

Problem Statement

Find the value of aa such that ∫0a1ex+4e−x+5 dx=ln⁡23.\int_{0}^{a}\frac{1}{e^{x}+4e^{-x}+5}\ dx=\ln \sqrt[3]{2}.
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