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TOT 1998 Spring OJ3 OM/ON = AB/CD

Source:

May 11, 2020
ratiogeometrymidpointsangle

Problem Statement

ABAB and CDCD are segments lying on the two sides of an angle whose vertex is OO. AA is between OO and BB, and CC is between OO and DD . The line connecting the midpoints of the segments ADAD and BCBC intersects ABAB at MM and CDCD at NN. Prove that OMON=ABCD\frac{OM}{ON}=\frac{AB}{CD}
(V Senderov)