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Durer Math Competition CD 1st Round - geometry
2014.C4
pentagon area AB=CD=EA=1, <ABC=<DEA=90^o, BC+DE=1 2013-14 Durer Round1 C4
pentagon area AB=CD=EA=1, <ABC=<DEA=90^o, BC+DE=1 2013-14 Durer Round1 C4
Source:
December 4, 2022
geometry
areas
pentagon
Durer
Problem Statement
A
B
C
D
E
ABCDE
A
BC
D
E
is a convex pentagon with
A
B
=
C
D
=
E
A
=
1
AB = CD = EA = 1
A
B
=
C
D
=
E
A
=
1
,
∠
A
B
C
=
∠
D
E
A
=
9
0
o
\angle ABC = \angle DEA = 90^o
∠
A
BC
=
∠
D
E
A
=
9
0
o
, and
B
C
+
D
E
=
1
BC + DE = 1
BC
+
D
E
=
1
. What is the area of the pentagon?
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