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2 sets from {3, 4, 5, ...,13, 14} (I Soros Olympiad 1994-95 R1 9.1 10.1)

Source:

July 30, 2021
combinatoricsSubsets

Problem Statement

Divide the set of twelve numbers A={3,4,5,...,13,14}A = \{3, 4, 5, ...,13, 14\} into two sets B B and CC 'of six numbers each according to this condition: for any two different numbers with B B their sum does not belong to B B and for any two different numbers from CC, the sum does not belong to CC.