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National and Regional Contests
China Contests
(China) National High School Mathematics League
2009 China Second Round Olympiad
2
Upper and lower bound of sum and ln(n)
Upper and lower bound of sum and ln(n)
Source: China Second Round 2009 Problem 2
February 18, 2012
logarithms
inequalities proposed
inequalities
Problem Statement
Let
n
n
n
be a positive integer. Prove that
−
1
<
∑
k
=
1
n
k
k
2
+
1
−
ln
n
≤
1
2
-1<\sum_{k=1}^{n}\frac{k}{k^2+1}-\ln n\le\frac{1}{2}
−
1
<
k
=
1
∑
n
k
2
+
1
k
−
ln
n
≤
2
1
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