MathDB
St Petersburgh 2008 #1

Source:

July 23, 2011
geometryincenterconicsparabolacircumcirclegeometry proposed

Problem Statement

The graph y=x2+ax+by=x^2+ax+b intersects any of the two axes at points AA, BB, and CC. The incenter of triangle ABCABC lies on the line y=xy=x. Prove that a+b+1=0a+b+1=0.
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