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DL = DM if < PAC = \< PBC

Source: Polish MO Recond Round 1983 p3

September 9, 2024
geometryequal segments

Problem Statement

The point P P lies inside the triangle ABC ABC , with PAC=PBC \measuredangle PAC = \measuredangle PBC . The points L L and M M are the projections P P onto the lines BC BC and CA CA , respectively, D D is the midpoint of the segment AB AB . Prove that DL=DM DL = DM .