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14
Prove that 45< x_1000 <45.1
Prove that 45< x_1000 <45.1
Source:
September 21, 2010
integration
algebra
Inequality
approximation
Sequence
recurrence relation
IMO Shortlist
Problem Statement
Let
x
0
=
5
x_0 = 5
x
0
=
5
and
x
n
+
1
=
x
n
+
1
x
n
(
n
=
0
,
1
,
2
,
…
)
x_{n+1} = x_n + \frac{1}{x_n} \ (n = 0, 1, 2, \ldots )
x
n
+
1
=
x
n
+
x
n
1
(
n
=
0
,
1
,
2
,
…
)
. Prove that
45
<
x
1000
<
45.1.
45 < x_{1000} < 45. 1.
45
<
x
1000
<
45.1.
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