MathDB
n = d2^2 + d3^3

Source: OMM 2008 1

July 19, 2014
number theory unsolvednumber theory

Problem Statement

Let 1=d1<d2<d3<⋯<dk=n1=d_1<d_2<d_3<\dots<d_k=n be the divisors of nn. Find all values of nn such that n=d22+d33n=d_2^2+d_3^3.
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