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2024 Chile TST Ibero.
4
Solve by titus??
Solve by titus??
Source:
October 23, 2024
TST
inequalities
algebra
TitusLemma
Chile
Problem Statement
Prove that if
a
a
a
,
b
b
b
, and
c
c
c
are positive real numbers, then the following inequality holds:
a
+
3
c
a
+
b
+
c
+
3
a
b
+
c
+
4
b
c
+
a
≥
6.
\frac{a + 3c}{a + b} + \frac{c + 3a}{b + c} + \frac{4b}{c + a} \geq 6.
a
+
b
a
+
3
c
+
b
+
c
c
+
3
a
+
c
+
a
4
b
≥
6.
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