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P(k) = \frac{k}{k +1} , find P(n+1), polynomial

Source: Switzerland - Swiss TST 2000 p14

February 19, 2020
polynomialalgebra

Problem Statement

The polynomial PP of degree nn satisfies P(k)=kk+1P(k) = \frac{k}{k +1} for k=0,1,2,...,nk = 0,1,2,...,n. Find P(n+1)P(n+1).