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Nice geometry in Iran.

Source: Iranian Third Round 2020 Geometry exam Problem2

November 18, 2020
geometry

Problem Statement

Triangle ABCABC with it's circumcircle Γ\Gamma is given. Points DD and EE are chosen on segment BCBC such that BAD=CAE\angle BAD=\angle CAE. The circle ω\omega is tangent to ADAD at AA with it's circumcenter lies on Γ\Gamma. Reflection of AA through BCBC is AA'. If the line AEA'E meet ω\omega at LL and KK. Then prove either BLBL and CKCK or BKBK and CLCL meet on Γ\Gamma.