MathDB
Tuymaada 2010, Junior League, Problem 7

Source:

July 18, 2010
geometryincentergeometric transformationreflectionsymmetrygeometry unsolved

Problem Statement

Let ABCABC be a triangle, II its incenter, ω\omega its incircle, PP a point such that PI⊥BCPI\perp BC and PA∥BCPA\parallel BC, Q∈(AB),R∈(AC)Q\in (AB), R\in (AC) such that QR∥BCQR\parallel BC and QRQR tangent to ω\omega. Show that ∠QPB=∠CPR\angle QPB = \angle CPR.
Back to ProblemsView on AoPS