MathDB
Error correcting codes: differing at three positions

Source: Bundeswettbewerb Mathematik 1971, round 2 problem 2

June 14, 2006
combinatorics proposedcombinatorics

Problem Statement

The inhabitants of a planet speak a language only using the letters AA and OO. To avoid mistakes, any two words of equal length differ at least on three positions. Show that there are not more than 2nn+1\frac{2^n}{n+1} words with nn letters.