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2017 Geometry Tiebreaker #1
2017 Geometry Tiebreaker #1
Source:
November 19, 2022
2017
Geometry Tiebreaker
Problem Statement
In
△
A
B
C
\triangle ABC
△
A
BC
, we have
∠
A
B
C
=
2
0
∘
\angle ABC=20^\circ
∠
A
BC
=
2
0
∘
. In addition,
D
D
D
is drawn on
A
B
‾
\overline{AB}
A
B
such that
A
C
=
C
D
=
B
D
AC=CD=BD
A
C
=
C
D
=
B
D
. Compute
∠
A
C
D
\angle ACD
∠
A
C
D
in degrees.
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