Coloring is hard
Source: 2019 China TST Test 3 P6
March 29, 2019
combinatoricsgraph theory
Problem Statement
Given positive integers , and , with . Every vertice of the graph is assigned to a positive integer in , such that for any two consecutive vertices in the graph, the integers they are assigned to, respectively, have difference no less than , and no more than .
A proper coloring of the graph is a coloring of the vertices, such that any two consecutive vertices are not the same color. It's given that there exist a proper subset of , such that for 's any proper coloring with colors, and for an arbitrary color , either all numbers in color appear in , or none of the numbers in color appear in .
Show that has a proper coloring within colors.