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2000 Switzerland Team Selection Test
8
sum f (k/1921) when f(x) = 4^x/ (4^x+2)
sum f (k/1921) when f(x) = 4^x/ (4^x+2)
Source: Switzerland - Swiss TST 2000 p8
February 19, 2020
algebra
Sum
Problem Statement
Let
f
(
x
)
=
4
x
4
x
+
2
f(x) = \frac{4^x}{4^x+2}
f
(
x
)
=
4
x
+
2
4
x
for
x
>
0
x > 0
x
>
0
. Evaluate
∑
k
=
1
1920
f
(
k
1921
)
\sum_{k=1}^{1920}f\left(\frac{k}{1921}\right)
∑
k
=
1
1920
f
(
1921
k
)
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